8085 is a Microprocessor which was developed by Intel in 1970s. All the instructions in this microprocessor are encoded in a single byte. Some of the instructions are followed by one or two bytes of data, which can be a memory address, an immediate operand or a port number.
In this post, we will write a program in 8085 to calculate 8-bit sum of N 8-bit numbers.
Algorithm
Start Address <- 2400H C <- M[Address] A <- 0 Address <- Address + 1 A <- A + M[Address] C <- C - 1 If C is not zero, goto 4 Address <- Address + 1 M[Address] <- A Stop
Flow Chart
Program
LXI H, 2400H
MOV C, M
MOV A, 00H
BACK: INX H
ADD M
DCR C
JNZ BACK
INX H
MOV M,A
RST 5
Example
2400H: 04 2401H: 01 2402H: 02 2403H: 03 2404H: 04 2405H: 0A -> Output
Check out our other 8085 programs
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- Program to convert binary number to decimal
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- Program to convert decimal to binary
Let us know in the comments if you are having any questions regarding this microprocessor program.
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