8085 is a Microprocessor which was developed by Intel in 1970s. All the instructions in this microprocessor are encoded in a single byte. Some of the instructions are followed by one or two bytes of data, which can be a memory address, an immediate operand or a port number.
In this post, we will write a program in 8085 to find the minimum of N numbers.
Start Address <- 2200H C <- M[Address] Address <- Address + 1 A <- M[Address] C <- C - 1 Address <- Address + 1 If A < M[Address], go to 10 A <- M[Address] Address <- Address + 1 C <- C - 1 If C != 0, go to 8 M[Address] <- A Stop
LXI H, 2200H MOV C, M INX H MOV A, M DCR C BACK: INX H CMP M JC NEXT MOV A, M NEXT: DCR C JNZ BACK INX H MOV M,A RST-5
2200H: 04 2201H: 02 2202H: 03 2203H: 04 2204H: 03 2205H: 02 -> Output
Check out our other 8085 programs
- Program to Calculate 8-bit Sum of N 8-bit Numbers
- Program to Find the Maximum of N Numbers
- Program to Find the Minimum of N Numbers
- Program to multiply two 8-bit numbers without using shifting multiplicand
- Program to multiply two 8-bit numbers using shifting multiplicand
- Program to divide a 16-bit number with an 8-bit number
- Program to find the HCF of two numbers
- Program to find the HCF of N numbers
- Program to convert binary number to decimal
- Program to convert binary number to decimal without using DAA
- Program to convert decimal to binary
Let us know in the comments if you are having any questions regarding this microprocessor program.
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