8085 is a Microprocessor which was developed by Intel in 1970s. All the instructions in this microprocessor are encoded in a single byte. Some of the instructions are followed by one or two bytes of data, which can be a memory address, an immediate operand or a port number.
In this post, we will write a program in 8085 to convert binary number to binary coded decimal(BCD).
Start Read binary number(C) Clear accumulator(A) D <- 0 A <- A + 1 Adjust for BCD count If CS != 1 go to 9 D <- D + 1 C <- C - 1 if CS != 0 go to 5 Store A as lower bits Store D as upper bits Stop
LXI H, 2100H MVI D, 00H XRA A MOV C, M LOOP: ADI 01H DAA JNC SKIP INR D SKIP: DCR C JNZ LOOP MOV L, A MOV H, D SHLD 2201H RST-5
2100H: F0 2101H: 40 -> lower bits 2105H: 02 -> upper bits // output is 240
Check out our other 8085 programs
- Program to Calculate 8-bit Sum of N 8-bit Numbers
- Program to Find the Maximum of N Numbers
- Program to Find the Minimum of N Numbers
- Program to multiply two 8-bit numbers without using shifting multiplicand
- Program to multiply two 8-bit numbers using shifting multiplicand
- Program to divide a 16-bit number with an 8-bit number
- Program to find the HCF of two numbers
- Program to find the HCF of N numbers
- Program to convert binary number to decimal
- Program to convert binary number to decimal without using DAA
- Program to convert decimal to binary
Let us know in the comments if you are having any questions regarding this microprocessor program.
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