8085 is a Microprocessor which was developed by Intel in 1970s. All the instructions in this microprocessor are encoded in a single byte. Some of the instructions are followed by one or two bytes of data, which can be a memory address, an immediate operand or a port number.

In this post, we will write a program in 8085 to convert decimal to binary number.

Algorithm

Start
Read the 8-bit number
Get upper 4-bits and store it as D
Get lower 4-bits and store it as C
D <- D x 10
A <- D + C
Store A
Stop

Flow Chart

Program

      LDA 2100H
      MOV B, A
      ANI 0FH
      MOV C, A
      MOV A, B
      ANI F0H
      JZ SKIP
      RRC
      RRC
      RRC
      RRC
      MOV D, A
      XRA A
      MVI E, 0AH
SUM:  ADD D
      DCR E
      JNZ SUM
SKIP: ADD C
      STA 2101H
      RST-5

Example

2100H: 72
2101H: 48  ->  output

Let us know in the comments if you are having any questions regarding this microprocessor program.

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