8085 is a Microprocessor which was developed by Intel in 1970s. All the instructions in this microprocessor are encoded in a single byte. Some of the instructions are followed by one or two bytes of data, which can be a memory address, an immediate operand or a port number.
In this post, we will write a program in 8085 to convert decimal to binary number.
Start Read the 8-bit number Get upper 4-bits and store it as D Get lower 4-bits and store it as C D <- D x 10 A <- D + C Store A Stop
LDA 2100H MOV B, A ANI 0FH MOV C, A MOV A, B ANI F0H JZ SKIP RRC RRC RRC RRC MOV D, A XRA A MVI E, 0AH SUM: ADD D DCR E JNZ SUM SKIP: ADD C STA 2101H RST-5
2100H: 72 2101H: 48 -> output
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