8085 is a Microprocessor which was developed by Intel in 1970s. All the instructions in this microprocessor are encoded in a single byte. Some of the instructions are followed by one or two bytes of data, which can be a memory address, an immediate operand or a port number.

In this post, we will write a program in 8085 to convert decimal to binary number.

### Algorithm

Start Read the 8-bit number Get upper 4-bits and store it as D Get lower 4-bits and store it as C D <- D x 10 A <- D + C Store A Stop

### Flow Chart

### Program

LDA 2100H MOV B, A ANI 0FH MOV C, A MOV A, B ANI F0H JZ SKIP RRC RRC RRC RRC MOV D, A XRA A MVI E, 0AH SUM: ADD D DCR E JNZ SUM SKIP: ADD C STA 2101H RST-5

### Example

2100H: 72 2101H: 48 -> output

#### Check out our other 8085 programs

- Program to Calculate 8-bit Sum of N 8-bit Numbers
- Program to Find the Maximum of N Numbers
- Program to Find the Minimum of N Numbers
- Program to multiply two 8-bit numbers without using shifting multiplicand
- Program to multiply two 8-bit numbers using shifting multiplicand
- Program to divide a 16-bit number with an 8-bit number
- Program to find the HCF of two numbers
- Program to find the HCF of N numbers
- Program to convert binary number to decimal
- Program to convert binary number to decimal without using DAA
- Program to convert decimal to binary

Let us know in the comments if you are having any questions regarding this microprocessor program.

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