8085 is a Microprocessor which was developed by Intel in 1970s. All the instructions in this microprocessor are encoded in a single byte. Some of the instructions are followed by one or two bytes of data, which can be a memory address, an immediate operand or a port number.
In this post, we will write a program in 8085 to find the HCF of two numbers.
Start Read first number(A) Read second number(B) Compare A and B If A - B = 0 go to 11 If A - B < 0 go to 9 A <- A - B go to 4 Swap A and B go to 4 Store A Stop
LXI H, 2100H MOV A, M INX H MOV B, M LOOP: CMP B JZ STORE JC EXG SUB B JMP LOOP EXG: MOV C, B MOV B, A MOV A, C JMP LOOP STORE: INX H MOV M, A RST-5
2100H: 06 2101H: 08 2102H: 02 -> output
Check out our other 8085 programs
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- Program to find the HCF of N numbers
- Program to convert binary number to decimal
- Program to convert binary number to decimal without using DAA
- Program to convert decimal to binary
Let us know in the comments if you are having any questions regarding this microprocessor program.
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