8085 is a Microprocessor which was developed by Intel in 1970s. All the instructions in this microprocessor are encoded in a single byte. Some of the instructions are followed by one or two bytes of data, which can be a memory address, an immediate operand or a port number.
In this post, we will write a program in 8085 to find the HCF of two numbers.
Algorithm
Start Read count(C) Read first number(A) C <- C - 1 Read the next number(B) Compare A and B If A - B = 0 go to 13 If A - B < 0 go to 11 A <- A - B go to 6 Swap A and B go to 6 C <- C - 1 If CS != 1 go to 5 Store A Stop
Flow Chart
Program
LXI H, 2100H
MOV C, M
DCR C
INX H
MOV A, M
LOOP2: INX H
MOV B, M
LOOP1: CMP B
JZ NEXT
JC EXG
SUB B
JMP LOOP1
EXG: MOV C, B
MOV B, A
MOV A, C
JMP LOOP1
NEXT: DCR C
JNZ LOOP2
INX H
MOV M, A
RST-5
Example
2100H: 04 2101H: 06 2102H: 08 2103H: 10 2104H: 12 2105H: 02 -> output
Check out our other 8085 programs
- Program to Calculate 8-bit Sum of N 8-bit Numbers
- Program to Find the Maximum of N Numbers
- Program to Find the Minimum of N Numbers
- Program to multiply two 8-bit numbers without using shifting multiplicand
- Program to multiply two 8-bit numbers using shifting multiplicand
- Program to divide a 16-bit number with an 8-bit number
- Program to find the HCF of two numbers
- Program to find the HCF of N numbers
- Program to convert binary number to decimal
- Program to convert binary number to decimal without using DAA
- Program to convert decimal to binary
Let us know in the comments if you are having any questions regarding this microprocessor program.
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