8085 is a Microprocessor which was developed by Intel in 1970s. All the instructions in this microprocessor are encoded in a single byte. Some of the instructions are followed by one or two bytes of data, which can be a memory address, an immediate operand or a port number.
In this post, we will write a program in 8085 to multiply two 8-bit numbers using shifting multiplicand.
Start Read multiplier Read multiplicand Extend multiplicand to double(16-bit) prod <- 0 count <- 8 Right shift multiplier If CS == 0 go to 10 prod <- prod + multiplicand multiplicand <- multiplicand x 2 (Left shift multiplicand) count <- count - 1 If count != 0 go to 7 Store prod Stop
LHLD 2100H MOV A, L MOV E, H MVI D, 00H LXI H, 0000H MVI C, 08H BACK: RAR JNC NEXT DAD D NEXT: XCHG DCR C JNZ BACK SHLD 2102H RST-5
2100H: 02 2101H: 03 2102H: 06 -> Output
Check out our other 8085 programs
- Program to Calculate 8-bit Sum of N 8-bit Numbers
- Program to Find the Maximum of N Numbers
- Program to Find the Minimum of N Numbers
- Program to multiply two 8-bit numbers without using shifting multiplicand
- Program to multiply two 8-bit numbers using shifting multiplicand
- Program to divide a 16-bit number with an 8-bit number
- Program to find the HCF of two numbers
- Program to find the HCF of N numbers
- Program to convert binary number to decimal
- Program to convert binary number to decimal without using DAA
- Program to convert decimal to binary
Let us know in the comments if you are having any questions regarding this microprocessor program.
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