8085 is a Microprocessor which was developed by Intel in 1970s. All the instructions in this microprocessor are encoded in a single byte. Some of the instructions are followed by one or two bytes of data, which can be a memory address, an immediate operand or a port number.

In this post, we will write a program in 8085 to multiply two 8-bit numbers using shifting multiplicand.

### Algorithm

Start Read multiplier Read multiplicand Extend multiplicand to double(16-bit) prod <- 0 count <- 8 Right shift multiplier If CS == 0 go to 10 prod <- prod + multiplicand multiplicand <- multiplicand x 2 (Left shift multiplicand) count <- count - 1 If count != 0 go to 7 Store prod Stop

### Flow Chart

### Program

LHLD 2100H MOV A, L MOV E, H MVI D, 00H LXI H, 0000H MVI C, 08H BACK: RAR JNC NEXT DAD D NEXT: XCHG DCR C JNZ BACK SHLD 2102H RST-5

### Example

2100H: 02 2101H: 03 2102H: 06 -> Output

#### Check out our other 8085 programs

- Program to Calculate 8-bit Sum of N 8-bit Numbers
- Program to Find the Maximum of N Numbers
- Program to Find the Minimum of N Numbers
- Program to multiply two 8-bit numbers without using shifting multiplicand
- Program to multiply two 8-bit numbers using shifting multiplicand
- Program to divide a 16-bit number with an 8-bit number
- Program to find the HCF of two numbers
- Program to find the HCF of N numbers
- Program to convert binary number to decimal
- Program to convert binary number to decimal without using DAA
- Program to convert decimal to binary

Let us know in the comments if you are having any questions regarding this microprocessor program.

And if you found this post helpful, then please help us by sharing this post with your friends. Thank You