8085 is a Microprocessor which was developed by Intel in 1970s. All the instructions in this microprocessor are encoded in a single byte. Some of the instructions are followed by one or two bytes of data, which can be a memory address, an immediate operand or a port number.
In this post, we will write a program in 8085 to divide a 16-bit number with an 8-bit number.
Algorithm
Start Read dividend(16 bit) Read divisor count <- 8 Left shift dividend Subtract divisor from upper 8-bits of dividend If CS != 1 go to 9 restore dividend Increment lower 8-bits of dividend count <- count - 1 If count != 0 go to 5 Store upper 8-bit dividend as remainder and lower 8-bit as quotient Stop
Flow Chart
Program
LHLD 2100H
LDA 2102H
MOV B, A
MVI C, 08H
BACK: DAD H
MOV A, H
SUB B
JC NEXT
MOV H, A
INR L
NEXT: DCR C
JNZ BACK
SHLD 2103H
RST-5
Example
2100H: 0C 2101H: 00 2102H: 07 2103H: 01 -> quotient 2104H: 05 -> remainder
Check out our other 8085 programs
- Program to Calculate 8-bit Sum of N 8-bit Numbers
- Program to Find the Maximum of N Numbers
- Program to Find the Minimum of N Numbers
- Program to multiply two 8-bit numbers without using shifting multiplicand
- Program to multiply two 8-bit numbers using shifting multiplicand
- Program to divide a 16-bit number with an 8-bit number
- Program to find the HCF of two numbers
- Program to find the HCF of N numbers
- Program to convert binary number to decimal
- Program to convert binary number to decimal without using DAA
- Program to convert decimal to binary
Let us know in the comments if you are having any questions regarding this microprocessor program.
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