8085 Program to convert binary number to decimal

8085 is a Microprocessor which was developed by Intel in 1970s. All the instructions in this microprocessor are encoded in a single byte. Some of the instructions are followed by one or two bytes of data, which can be a memory address, an immediate operand or a port number.

In this post, we will write a program in 8085 to convert binary number to binary coded decimal(BCD).

Algorithm

Start
Read binary number(C)
Clear accumulator(A)
D <- 0
A <- A + 1
Adjust for BCD count
If CS != 1 go to 9
D <- D + 1
C <- C - 1
if CS != 0 go to 5
Store A as lower bits
Store D as upper bits
Stop

Flow Chart

Program

      LXI H, 2100H
      MVI D, 00H
      XRA A
      MOV C, M
LOOP: ADI 01H
      DAA
      JNC SKIP
      INR D
SKIP: DCR C
      JNZ LOOP
      MOV L, A
      MOV H, D
      SHLD 2201H
      RST-5

Example

2100H: F0
2101H: 40  ->  lower bits
2105H: 02  ->  upper bits
// output is 240

Check out our other 8085 programs

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• Program to find the HCF of N numbers
• Program to convert binary number to decimal
• Program to convert binary number to decimal without using DAA
• Program to convert decimal to binary

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