8085 is a Microprocessor which was developed by Intel in 1970s. All the instructions in this microprocessor are encoded in a single byte. Some of the instructions are followed by one or two bytes of data, which can be a memory address, an immediate operand or a port number.
In this post, we will write a program in 8085 to convert binary number to binary coded decimal(BCD) without using DAA operation.
Algorithm
Start Clear D and E registers to account for hundreds and tens Load data in A Compare A with 64H If CS = 1 go to 9 A <- A - 64H E <- E + 1 Go to 4 Compare A with 0AH if CS = 1 go to 14 A <- A - 0AH D <- D + 1 go to C <- A A <- D Rotate left A 4 times Combine unit and tens to form lower bit result Save hundreds as upper bits and combined result as lower bit Stop
Flow Chart
Program
MVI E, 00H
MOV D, E
LDA 2100H
HUND: CPI 64H
JC TEN
SUI 64H
INR E
JMP HUND
TEN: CPI 0AH
JC UNIT
SUI 0AH
INR D
JMP TEN
UNIT: MOV C, A
MOV A, D
RLC
RLC
RLC
RLC
ADD C
STA 2101H
MOV A, E
STA 2102H
RST-5
Example
2100H: FF 2101H: 55 -> lower bits 2105H: 02 -> upper bits // output is 255
Check out our other 8085 programs
- Program to Calculate 8-bit Sum of N 8-bit Numbers
- Program to Find the Maximum of N Numbers
- Program to Find the Minimum of N Numbers
- Program to multiply two 8-bit numbers without using shifting multiplicand
- Program to multiply two 8-bit numbers using shifting multiplicand
- Program to divide a 16-bit number with an 8-bit number
- Program to find the HCF of two numbers
- Program to find the HCF of N numbers
- Program to convert binary number to decimal
- Program to convert binary number to decimal without using DAA
- Program to convert decimal to binary
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