8085 is a Microprocessor which was developed by Intel in 1970s. All the instructions in this microprocessor are encoded in a single byte. Some of the instructions are followed by one or two bytes of data, which can be a memory address, an immediate operand or a port number.
In this post, we will write a program in 8085 to find the HCF of two numbers.
Algorithm
Start Read first number(A) Read second number(B) Compare A and B If A - B = 0 go to 11 If A - B < 0 go to 9 A <- A - B go to 4 Swap A and B go to 4 Store A Stop
Flow Chart
Program
LXI H, 2100H
MOV A, M
INX H
MOV B, M
LOOP: CMP B
JZ STORE
JC EXG
SUB B
JMP LOOP
EXG: MOV C, B
MOV B, A
MOV A, C
JMP LOOP
STORE: INX H
MOV M, A
RST-5
Example
2100H: 06 2101H: 08 2102H: 02 -> output
Check out our other 8085 programs
- Program to Calculate 8-bit Sum of N 8-bit Numbers
- Program to Find the Maximum of N Numbers
- Program to Find the Minimum of N Numbers
- Program to multiply two 8-bit numbers without using shifting multiplicand
- Program to multiply two 8-bit numbers using shifting multiplicand
- Program to divide a 16-bit number with an 8-bit number
- Program to find the HCF of two numbers
- Program to find the HCF of N numbers
- Program to convert binary number to decimal
- Program to convert binary number to decimal without using DAA
- Program to convert decimal to binary
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